A (−5, 3)B (3, −3)
What is the distance of AB?
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Answer:
AB = 10
Step-by-step explanation:
Given:
Two points are given [tex]A(-5, 3)[/tex] and [tex]B(3, -3)[/tex]
The distance formula of the two points is.
[tex]AB=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]
Put given values in above equation.
[tex]x=\sqrt{(3-(-5))^{2}+(-3-3)^{2}}[/tex]
[tex]x=\sqrt{(3+5)^{2}+(-6)^{2}}[/tex]
[tex]x=\sqrt{(8)^{2}+(-6)^{2}}[/tex]
[tex]x=\sqrt{64+36}[/tex]
[tex]x=\sqrt{100}[/tex]
[tex]x=10[/tex]
Therefore, the distance of the line AB is 10
Answer:
14 units
Step-by-step explanation:
you count rise over run so you move down from point a until you are on the same y value as b and the the distance from there to b so you go down 6 units and right 8 units which all together is 14 units
hope this helps!