Respuesta :

Answer:

AB = 10

Step-by-step explanation:

Given:

Two points are given [tex]A(-5, 3)[/tex] and [tex]B(3, -3)[/tex]

The distance formula of the two points is.

[tex]AB=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]

Put given values in above equation.

[tex]x=\sqrt{(3-(-5))^{2}+(-3-3)^{2}}[/tex]

[tex]x=\sqrt{(3+5)^{2}+(-6)^{2}}[/tex]

[tex]x=\sqrt{(8)^{2}+(-6)^{2}}[/tex]

[tex]x=\sqrt{64+36}[/tex]

[tex]x=\sqrt{100}[/tex]

[tex]x=10[/tex]

Therefore, the distance of the line AB is 10

Answer:

14 units

Step-by-step explanation:

you count rise over run so you move down from point a until you are on the same y value as b and the the distance from there to b so you go down 6 units and right 8 units which all together is 14 units

hope this helps!