LIn lines the bottom of her first pan with aluminum foil. The area of the rectangle piece of foil is 11 1/4 square inches. Its length is 4 1/2 inches what is the width of the foli.

Respuesta :

Width of foil is [tex]2\frac{1}{2}[/tex] inches

Solution:

Given that area of the rectangle piece of foil is [tex]11\frac{1}{4}[/tex] square inches

Its length is [tex]4\frac{1}{2}[/tex] inches

To find: width of foil

The area of rectangle is given as:

To find the area of a rectangle, we multiply the length by the width

[tex]\text{ area of rectangle}= length \times width[/tex]

Substituting the given values in above formula,

[tex]11\frac{1}{4} = 4\frac{1}{2} \times width[/tex]

Let us solve above expression to find width

[tex]\frac{4 \times 11 + 1}{4} = \frac{2 \times 4 + 1}{2} \times width\\\\\frac{45}{4} = \frac{9}{2} \times width\\\\width = \frac{45}{4} \times \frac{2}{9}\\\\width = \frac{5}{2} = 2\frac{1}{2}[/tex]

Therefore width of foil is [tex]2\frac{1}{2}[/tex] inches

Answer:

2.5

Step-by-step explanation: