Respuesta :
Width of foil is [tex]2\frac{1}{2}[/tex] inches
Solution:
Given that area of the rectangle piece of foil is [tex]11\frac{1}{4}[/tex] square inches
Its length is [tex]4\frac{1}{2}[/tex] inches
To find: width of foil
The area of rectangle is given as:
To find the area of a rectangle, we multiply the length by the width
[tex]\text{ area of rectangle}= length \times width[/tex]
Substituting the given values in above formula,
[tex]11\frac{1}{4} = 4\frac{1}{2} \times width[/tex]
Let us solve above expression to find width
[tex]\frac{4 \times 11 + 1}{4} = \frac{2 \times 4 + 1}{2} \times width\\\\\frac{45}{4} = \frac{9}{2} \times width\\\\width = \frac{45}{4} \times \frac{2}{9}\\\\width = \frac{5}{2} = 2\frac{1}{2}[/tex]
Therefore width of foil is [tex]2\frac{1}{2}[/tex] inches