Answer:
When electron drops from n=6 to n=2, it emits wavelength of 410 nm which gives violet color.
Explanation:
Using Rydberg's Equation:
[tex]\frac{1}{\lambda } = R\left ( \frac{1}{n_{f}^{2}}-\frac{1}{n_{i}^{2}} \right )[/tex]
Here
R= Rydberg's constant = [tex]1.097\times 10^{7}\ m^{-1}[/tex]
[tex]{\lambda }[/tex] = Wavelength of photon emitted
[tex]{n_{f}}[/tex] = 2
[tex]{n_{i}[/tex] = 6
Put the values in the formula:
[tex]\frac{1}{\lambda } = 1.097\times 10^{7}\left ( \frac{1}{2^{2}}-\frac{1}{6^{2}} \right )[/tex]
[tex]\frac{1}{\lambda } = 1.097\times 10^{7}\times 0.22[/tex]
[tex]\frac{1}{\lambda } = 2.437\times 10^{6} \ m^{-1}[/tex]
[tex]\lambda = \frac{1}{2.478\times 10^{6}}[/tex]
[tex]\lambda = 4.10\times 10^{-7}[/tex] m
[tex]\lambda[/tex] = 410 nm
(1 m = [tex]10^{-9}[/tex])
This wavelength( 410 nm) is emitted by VIOLET color
