Answer:
37.5 mg
Step-by-step explanation:
So, The half life of plutonium = 2 days
Original amount = 1200 mg
So the number of halflive periods in 10 days = 10/2 =5
SO we use the formula:
[tex]\frac{P}{2^n}[/tex]
Where P is the original amount and n is the amount of halflife periods.
By substituting we get:
[tex]\frac{1200}{2^5} \\\\\frac{1200}{32}=37.5[/tex]
Answer:
37.5 mg
Step-by-step explanation:
Half life of Polonium-218 = 2 days
Initial sample mass = 1200 mg
Time interval = 10 days.
Number of half lives in 10 days = [tex]\[\frac{10}{2}\][/tex] = 5
After 5 half lives the initial sample will reduce to [tex]\[\frac{1}{2^{5}}\][/tex] of its initial amount.
So 1200 mg will reduce to [tex]\[\frac{1200}{2^{5}}\][/tex] = 37.5 mg
The resultant sample weight will become 37.5 milligram after 10 days.
