Answer:
e.none of these
Step-by-step explanation:
Computations For CC for Fraction defective
Sample No d p=d/100
1 0 0
2 0 0
3 2 0.02
4 1 0.01
5 0 0
6 1 0.01
7 2 0.02
8 0 0
Total 0.06
[tex]\overline{p} =\frac{1}{k}\sum p=\frac{0.06}{8} =0.0075[/tex]
[tex]\overline{q} =1- 0.0075= 0.9925[/tex]
3 sigma control limits for p chart are given by:
[tex]\overline{p} \pm 3\sqrt{\overline{p}\overline{q}/n}\Rightarrow 0.0075\pm 3\sqrt{\frac{0.0075*0.9925}{100}}[/tex]
[tex]= 0.0075\pm0.0259\Rightarrow ( 0.0334,0 )[/tex]
hence option e is correct