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Consider a paint-drying situation in which drying time for a test specimen is normally distributed with s = 6. The hypotheses H0: µ = 74 and Ha: µ < 74 are to be tested using a random sample of n = 25 observations.(a) How many standard deviations (of X) below the null value is x = 72.3? (Round your answer to two decimal places.)(b) If x = 72.3, what is the conclusion using a = 0.01? (Round your answers to two decimal places.)test statistic z =critical value z =What can you conclude?

Respuesta :

Answer:

There is no statistical evidence to support the claim that the mean is elss than 74.

Step-by-step explanation:

Given that  a paint-drying situation in which drying time for a test specimen is normally distributed with s = 6.

The hypotheses H0: µ = 74 and Ha: µ < 74

are to be tested using a random sample of n = 25 observations

a) Z = [tex]\frac{72.3-74}{\frac{6}{\sqrt{25} } } \\=-1.417[/tex]

ie. -1.417 std deviations to the left of mean.

b) p value = 0.078241

Since p > 0.01 , our alpha, accept H0

There is no statistical evidence to support the claim that the mean is elss than 74.

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