Respuesta :
Answer: The total pressure of container at equilibrium is 0.431 bar
Explanation:
We are given:
Pressure of hydrogen sulfide = 0.240 bar
The given chemical equation follows:
[tex]H_2S(g)\rightleftharpoons H_2(g)+S(g)[/tex]
Initial: 0.240
At eqllm: 0.240-x x x
The expression of [tex]K_p[/tex] for above equation follows:
[tex]K_p=\frac{p_{H_2}\times p_S}{p_{H_2S}}[/tex]
We are given:
[tex]K_p=0.746[/tex]
Putting values in above expression, we get:
[tex]0.746=\frac{x\times x}{0.240-x}\\\\x=0.191,-0.940[/tex]
Neglecting the negative value of 'x' because pressure cannot be negative.
So, the equilibrium pressure of hydrogen gas = x = 0.191 bar
The equilibrium pressure of sulfur gas = x = 0.191 bar
The equilibrium pressure of hydrogen sulfide gas = (0.240 - x) = (0.240 - 0.191) = 0.049 bar
Total pressure of the container at equilibrium = [tex]p_{H_2}+p_{S}+p_{H_2S}[/tex]
Total pressure of the container at equilibrium = 0.191 + 0.191 + 0.049 = 0.431 bar
Hence, the total pressure of container at equilibrium is 0.431 bar
