Answer:
[tex]\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}[/tex]
Step-by-step explanation:
[tex]\overrightarrow{P_1P_2}=(P_2-P_1)\cdot(\textbf{i},\textbf{j},\textbf{k})=(-5-0)\textbf{i}+(-3-1)\textbf{j}+(-9-(-3))\textbf{k}\\\\\overrightarrow{P_1P_2}=-5\textbf{i}-4\textbf{j}-6\textbf{k}[/tex]