Identify the oxidation number of the highlighted carbon atoms in each of the molecules.

a. In molecule A a central carbon atom is bonded to two C H 3 groups and an O atom through a double bond.
b. The central carbon atom is highlighted.
c. In molecule B, a central carbon atom is bonded to two C H 3 groups, an O H group, and an H atom.
d. The central carbon atom is highlighted.

Respuesta :

Answer:

A) Oxidation state of carbon is +2

B) Oxidation state of carbon is 0

Explanation:

In the first question  , the compound is propanone.

While assigning oxidation states ,

  • We must see to that , the electrons in the bond moves towards the most electronegative atom.
  • If they are equally electronegative , each of them gets 0 oxidation state respectively.
  • And if there is one bond , the oxidation state obtained by the electronegative atom is -1 and the other is +1.
  • The order of electronegativity is as follows :

[tex]O>C>H[/tex]

  • Thus [tex]O[/tex] always gets -1 and [tex]H[/tex] always gets +1 in these two compounds.
  • The carbon - carbon bond will give 0 oxidation state.

A) According to these rules the Oxidation state of carbon is +2

B) According to these rules the Oxidation state of carbon is 0

  • Diagram attached below
  • The direction of the arrows in the diagram represents the movement of electron

Ver imagen kalyani62

The oxidation number of the central  carbon in molecule A is +2 while the oxidation number of the central  carbon carbon in molecule B is 0.

In organic compounds, the oxidation state of carbon in organic compounds is as follows;

  • In the C - C, carbon has an oxidation number of zero
  • In the C - H, carbon has an oxidation mumber of -1
  • When carbon is bonded to an electronegative atom, the oxidation number of carbon is +1

The first compound is acetone shown in image (1), the oxidation number of carbon bonded to two C H 3 groups and an O atom through a double bond is; 0 + 0 +2 = +2

In the second compound which is propan - 2- ol(image 2), the oxidation number of  the central carbon atom is 0 + 0 + 1 - 1 = 0

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Ver imagen pstnonsonjoku
Ver imagen pstnonsonjoku