Respuesta :
Answer:
The total potential energy is 34.307 kJ
Solution:
As per the question:
Mass of the stuntman, m = 70.0 kg
Length of the unstretched cord, l = 15.0 m
Height of the cord, H = 50.0 m
The stretched length of the cord, [tex]\Delta l = 44.0\ m[/tex]
Spring constant of the cord, k = 71.8 N/m
Now,
The total potential energy is given as the sum of gravitational potential energy and elastic potential energy:
The height attained, h = H - [tex]\Delta l[/tex] = 50.0 - 44.0 = 6.0 m
PE_{G} = mgh = [tex]70\times 9.8\times 6.0 = 4116\ J = 4.116\ kJ[/tex]
Now, the elastic potential energy:
x = l - [tex]\Delta l[/tex] = 44.0 - 15.0 = 29.0 m
[tex]PE_{E} = \frac{1}{2}kx^{2} = \frac{1}{2}\times 71.8\times (29)^{2} = 30.191\ kJ[/tex]
The Total Potential Energy:
[tex]PE_{G} + PE_{E} = 4.116 + 30.191 = 34.307\ kJ[/tex]
