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A 18.6 m long steel beam is accidentally dropped by a construction crane from a height of 8.78 m. The horizontal component of the Earth’s magnetic field over the region is 12.7 µT. The acceleration of gravity is 9.8 m/s 2 . What is the induced emf in the beam just before impact with the Earth, assuming its long dimension remains in a horizontal plane, oriented perpendicularly to the horizontal component of the Earth’s magnetic field? Answer in units of mV

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olucheyi

Answer: Induced emf is 3.1mV

Explanation:

Speed, s =√ 2gh , where g is acceleration fue to gravity and h is height

S = √ 2 x 9.8 x 8.78

S = 13.12m/sec

Emf = Bsl

= 18 6 x 13.12 x 12.7 x 10^-6T

= 3.099 x 10^-3V

Approximately,

3.1mV

Therefore, the induced emf is 3.1mV

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