Answer:
Sample Slope:_-6.8565_-P Value:__0.000___-Is the model effective: yes
Step-by-step explanation:
Hello!
The estimated regression equation is : Y= 93.9 - 6.86X
Where Y is the dependent variable and X is the independent variable.
PredictorCoef SECoef T P
Constant 93.874 4.763 19.71 0.000
X -6.8565 0.8001 -8.57 0.000
Looking at the data that corresponds to the estimation of the regression:
The row of "Constant " corresponds to the estimation regarding α (y-intercept of the line)
a= 93.874 (Point estimation of α)
Sa= 4.763 (Standard deviation of a)
T= 19.71 (Is the value of the corresponding statistic for the hypothesis H₀: α = 0 vs H₁: α ≠ 0)
And P= 0.000 is the P-value for the test mentioned above.
The row called "X" has all the information regarding the estimation of the slope.
b= -6.8565 (Point estimation of β)
Sb= 0.8001 (Standard deviation of b)
T= -8.57 (Is the value of the corresponding statistic for the hypothesis H₀: β = 0 vs H₁: β ≠ 0)
And P= 0.000 is the P-value for the test mentioned above.
With the given data, at a significance level of 5% the decision is to reject the null hypothesis (H₀: β = 0) which means that there is a modification of the population mean of the dependent variable when the independent variable varies in one unit. At the same level, you could say that the model is effective.
I hope it helps!
