Answer:
a) there is evidence that the water temperature is acceptable at
α = 0.05
b) p = 0.008536
c) If hyp mean is 106, then test statistic=-4/2/3 = -6
p = 0.000162
Prob = 0.000162
Step-by-step explanation:
Given that X, mean water temperature downstream from a power plant cooling tower discharge pipe should be no more than 104°F.
[tex]n=9\\\sigma = 2\\Std error = 2/3 = 0.667\\\bar x = 102[/tex]
[tex]H_0: \bar x = 104\\H_a: \bar X <104[/tex]
(left tailed test at 5% significance level)
Mean difference = -2
Test statistic t = mean difference/std error = -3
df =8
p = 0.008536
Since p <0.05 we reject null hypotehsi
a) there is evidence that the water temperature is acceptable at
α = 0.05
b) p = 0.008536
c) If hyp mean is 106, then test statistic=-4/2/3 = -6
p = 0.000162
Prob = 0.000162