Answer:
2120.38915 Hz
0.17638 m
Explanation:
[tex]f_s[/tex] = Frequency of sound emitted by the engine = 2000 Hz
[tex]v_t[/tex] = Speed of truck = 20 m/s
[tex]v_s[/tex] = Speed of fire engine = 30 m/s
v = Speed of sound in air = 344 m/s
Frequency of the fire engine is given by
[tex]f_t=f_s\dfrac{v-v_t}{v-v_s}\\\Rightarrow f_t=2000\dfrac{344-20}{344-30}\\\Rightarrow f_t=2063.69426\ Hz[/tex]
The frequency of the fire engine that is heard is 2063.69426 Hz
For the engine
[tex]f_e=f_t\dfrac{v+v_s}{v-v_t}\\\Rightarrow f_e=2063.69426\dfrac{344+30}{344+20}\\\Rightarrow f_e=2120.38915\ Hz[/tex]
The frequency that the fire engine's driver hears reflected from the back of the truck is 2120.38915 Hz
Wavelength is given by
[tex]\lambda=\dfrac{v+v_s}{f_t}\\\Rightarrow \lambda=\dfrac{344+20}{2063.69426}\\\Rightarrow \lambda=0.17638\ m[/tex]
The wavelength would be 0.17638 m