A tube is in the shape of a right circular cylinder the height is increasing at the rate of 1.5 inches/sec while the radius is decreasing that the rate of 0.5 inches/sec at the time that the radius is 4 inches and the length is 14 inches, how is the lateral surface area of the tube changing?

Respuesta :

Answer:

  -2π square inches per second

Step-by-step explanation:

The lateral surface area is the product of the height and circumference, so can be described by the formula ...

  LA = 2πrh

Differentiating with respect to time, we get ...

  LA' = 2π(r'h +rh')

Filling in the given values, gives ...

  LA' = 2π((-0.5 in/s)(14 in) + (4 in)(1.5 in/s)) = 2π(-7 in²/s +6 in²/s)

  = -2π in²/s ≈ -6.283 in²/s . . . . rate of change of lateral area