Answer:
Explanation:
mass of airplane, m = 12000 kg
altitude, h = 10 km = 10,000 m
velocity, v = 175 m/s
(a) Angular momentum
L = m x v x h x Sin 90
L = 12000 x 10,000 x 175
L = 2.1 x 10^10 kg m^2/s
(b) As there is no external torque, so the angular momentum remains constant.
The magnitude of the airplane's angular momentum (in kg-m2/s) relative to a ground observer directly below the plane will be L = 2.1 x 10^10 kg m^2/s
In physics, angular momentum (rarely, moment of momentum or rotational momentum) is the rotational motion of linear momentum. It is an important quantity in physics because it is a conserved quantity
The total angular momentum of a closed system remains constant. Angular momentum has both a direction and a magnitude, and both are conserved.
It is given that
mass of airplane, m = 12000 kg
altitude, h = 10 km = 10,000 m
velocity, v = 175 m/s
(a) Angular momentum of an airoplane
L = m x v x h x Sin 90
L = 12000 x 10,000 x 175
L = 2.1 x 10^10 kg m^2/s
(b) As there is no external torque, so the angular momentum remains constant.
Hence the magnitude of the airplane's angular momentum (in kg-m2/s) relative to a ground observer directly below the plane will be L = 2.1 x 10^10 kg m^2/s
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