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The combustion of ethane ( C 2 H 6 ) (C2H6) produces carbon dioxide and steam. 2 C 2 H 6 ( g ) + 7 O 2 ( g ) ⟶ 4 CO 2 ( g ) + 6 H 2 O ( g ) 2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(g) How many moles of CO 2 CO2 are produced when 5.80 mol 5.80 mol of ethane is burned in an excess of oxygen?

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Answer:

There is a production of 11.6 moles of CO₂

Explanation:

The reaction is this:

2C₂H₆(g)  +  7O₂(g)  ⟶  4CO₂(g)  +  6H₂O(g)

2 moles of ethane reacts with 7 moles of oxygen, to make 4 mol of dioxide and 6 moles of water vapor.

If the oxygen is in excess, we make the calculate with the ethane (limiting reactant)

2 moles of ethane produce 4 moles of dioxide

5.8 moles of ethane produce (5.8  .4)/2 = 11.6 moles

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