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In a​ survey, 33​% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result to be too​ high, so she randomly selected 150 pet owners and discovered that 46 of them spoke to their pet on the telephone. Does the veterinarian have a right to be​ skeptical? Use the alphaequals0.01 level of significance. What are the null and alternative hypotheses?Use technology to find the P-Value.

Respuesta :

Answer:

p value =0.544

Step-by-step explanation:

Given that in a survey,  33​% of the respondents stated that they talk to their pets on the telephone.

[tex]H_0: p = 0.33\\H_a: p <0.33[/tex]

(left tailed test at 1% level)

Sample proportion p = [tex]\frac{46}{150} \\=0.3067[/tex]

Assuming H0 to be true, std error of proportion

= [tex]\sqrt{\frac{0.33*0.67}{150} } \\=0.0384[/tex]

p difference = -0.0233

Test statistic Z = p difference/std error

= -0.6067

p value = 0.544

Since p > alpha, we accept H0

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