Answer:
At the 5% level of significance, it is not reasonable to conclude that students at West Virginia sleep less than the typical American
Step-by-step explanation:
Given that according to a recent survey, Americans get a mean of 7 hours of sleep per night. A random sample of 50 students at West Virginia University revealed the mean length of time slept last night was 6 hours and 48 minutes (6.8 hours). The standard deviation of the sample was 0.9 hours.
n =50
Std error = [tex]\frac{s}{\sqrt{n} } \\=0.1273[/tex]
Since sample std dev is only known, we can use t test.
[tex]H_0: \bar x = 7\\H_a: \bar x <7[/tex]
(left tailed test at 5% level)
Mean difference = -0.12
Test statistic t = mean diff/std error = -0.9429
p value for t test with d f= 49 is 0.175
Since p>alpha we accept null H0
At the 5% level of significance, it is not reasonable to conclude that students at West Virginia sleep less than the typical American
