The freezing point of helium is –270°C. The freezing point of xenon is –112°C. Both of these are in the noble gas family. Which of the following statements is supported by these data?

A)Helium and xenon form highly polar molecules.
B)As the molecular weight of the noble gas increases, the freezing point decreases.
C)The London dispersion forces between the helium molecules are greater than the London dispersion between the xenon molecules.
D)The London dispersion forces between the helium molecules are less than the London dispersion forces between the xenon molecules.
E)None of these.

Respuesta :

Answer:

B and D

Explanation:

Noble gases the elements which have complete outermost shell of their electronic configuration and do not need to react with any element under normal circumstances.

As the molecular size of the noble gas increases down the group, two things happen. Larger and heavier atoms and molecules exhibit stronger dispersion forces than smaller and lighter ones. Therefore, they have close connection and therefore needed less energy to gather around each other. Xenon gas has a large atomic size and hence have stronger London dispersion force than Helium atom.

So, option B and D are correct for the given question.

B) As the molecular weight of the noble gas increases, the freezing point decreases.

D)The London dispersion forces between the helium molecules are less than the London dispersion forces between the xenon molecules.

NOBLE GASES:

1. They have completely filled shells that means having stable electronic configuration.

2. As the molecular size of the noble gas increases down the group. Larger and heavier atoms and molecules exhibit stronger dispersion forces than smaller and lighter ones.

  • Therefore, they have close connection and therefore needed less energy to gather around each other.

Xenon gas has a large atomic size and hence have stronger London dispersion force than Helium atom.

Thus, correct options are B and D.

Find more information about "Noble gases" here:

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