Answer:
2093 J is released by the burning of the nut
Explanation:
Calorimetry formula: Q = m.C.ΔT
Q = 50g . C .ΔT
C is the specific heat of water: 4.186 J/g°C
ΔT = Final temperature - Initial temperature
ΔT = 35° - 25° = 10°C
Q = 50g . 4.186 J/g°C . 10°C → 2093 joules
Answer:
There is 2092 J of heat released
Explanation:
Step 1: Data given
Mass of the water = 50.0 grams
Initial temperature = 25.0 °C
Final temperature = 35.0 °C
Specific heat of water = 4.184 J/g°C
Step 2: Calculate the heat released
Q = m*c*ΔT
⇒ m = the mass of water = 50.0 grams
⇒ c = the specific heat of water = 4.184 J/g°C
⇒ ΔT = The change of temperature = T2 - T1 = 35.0 - 25.0 = 10.0 °C
Q = 50.0g * 4.184 J/g°C * 10.0°C
Q = 2092 J
There is 2092 J of heat released
