Answer:
Specific heat of liquid [tex]1.258 \ J/g^0C.[/tex]
Explanation:
We know in thermal equilibrium :
Loss in heat by iron block = Gain in heat by liquid .
Specific heat of iron = 0.45 [tex]J/g^0C.[/tex] { source internet }
Now , loss in heat by iron block = [tex]mC_{iron}\Delta T=450\times 0.45\times 57.6=11664\ J.[/tex]
Heat gain by liquid=[tex]mC_{liquid}\Delta T=450\times C_{liquid}\times 20.6=9270\times C_{liquid}.[/tex]
Equating both we get :
[tex]C_{liquid}=1.258 \ J/g^0C.[/tex]
