Answer:
m = 7.48 kg
Explanation:
force (f) = 11,500 N
length of barrel (s) = 1.7 m
angle above the ground = 49.3 degrees
acceleration due to gravity (g) = 9.8 m/s^{2}
initial velocity (u) = 0 m/s
final velocity (v) = 72.3 m/s
mass (m) = ?
force = mass (m) x acceleration (a)
acceleration (a) = force / mass (m)
acceleration (a) = 11500 / m
applying the equation of motion [tex]v^{2} = u^{2} + 2as[/tex] , we can get the mass
[tex]72.3^{2} = 0^{2} + (2 x \frac{11500}{m} x 1.7 )[/tex]
5227.3 = 0 + [tex]\frac{39100}{m}[/tex]
m = [tex]\frac{39100}{5227.3}[/tex]
m = 7.48 kg
The mass of the object is a scalar quantity. The mass of the cannonball is 7.47 kg.
The mass is defined as the total quantity of matter contained by a physical object.
Given that the force F exerted on a cannonball is 11500 N and the length l of the barrel is 1.7 m. The acceleration of gravity g is 9.8 m/s2. The angle above the ground is 49.3 degrees. The initial velocity u of the ball is 0 m/s and the final velocity v is 72.3 m/s.
The acceleration on the ball is calculated as given below.
[tex]F = ma[/tex]
[tex]11500 = ma[/tex]
[tex]a = \dfrac {11500}{m}[/tex]
By the equation of motion, we get,
[tex]v^2 = u^2 + 2as[/tex]
[tex]72.3^2 = 0^2 + 2 \times (\dfrac {11500}{m}) \times l[/tex]
[tex]5227.29 = 2 \times \dfrac{11500}{m}\times 1.7[/tex]
[tex]m = \dfrac{39100}{5227.29}[/tex]
[tex]m = 7.47 \;\rm kg[/tex]
Hence we can conclude that the mass of the cannonball is 7.47 kg.
To know more about the mass and acceleration, follow the link given below.
https://brainly.com/question/1046166.
