Answer:
[tex]\dfrac{N_s}{N_p}=2.08219[/tex]
[tex]\dfrac{I_{sn}}{I_{so}}=0.48289[/tex]
Explanation:
V denotes voltage
I denotes current
p denotes primary
s denotes secondary
o denotes old
n denotes new
N denotes number of turns
For transformers we have the following relation
[tex]\dfrac{V_s}{V_p}=\dfrac{N_s}{N_p}\\\Rightarrow \dfrac{N_s}{N_p}=\dfrac{760}{365}\\\Rightarrow \dfrac{N_s}{N_p}=2.08219[/tex]
The required ratio is [tex]\dfrac{N_s}{N_p}=2.08219[/tex]
For current
[tex]\dfrac{I_{so}}{I_{sn}}=\dfrac{V_{sn}}{V_{sn}}\\\Rightarrow \dfrac{I_{sn}}{I_{so}}=\dfrac{367}{760}\\\Rightarrow \dfrac{I_{sn}}{I_{so}}=0.48289[/tex]
The required ratio is [tex]\dfrac{I_{sn}}{I_{so}}=0.48289[/tex]