contestada

They worked a total of 285 hours at the shelter last summer.Alexis worked 15 hours less then becca. Cindy worked 4 more then twice as many hours as becca at the shelter. Alexis worked 15 hours less then becca cindy worked 4 more than twice as many as becca

Respuesta :

Answer:

The time spend by Alexis is 59 hours  

The time spend by Becca is 74 hours    

The time spend by Cindy is 152 hours

Step-by-step explanation:

Given as :

The total time spend on working together = 285 hours

Alexis worked 15 hours less then Becca.

Cindy worked 4 more then twice as many hours as Becca at the shelter.

Now , Let The time spend by Alexis = A hours

The time spend by Becca = B hours

The time spend by Cindy = C hours

So, According to question

The total time spend on working together = A + B + C

I.e A + B + C = 285          .........1

A = B - 15              ............2

C = 4 + 2 B           ............3

Now, Solving the equations

Put the values of A ana C from eq 2 and 3 into eq 1

So, (B - 15) + B + (4 + 2 B) = 285  

Or, (B + B + 2 B) + (4 - 15) = 285

or, 4 B - 11 = 285

or, 4 B = 285 + 11

or, 4 B = 296

∴  B = [tex]\frac{296}{4}[/tex]

I.e B = 74

So, The time spend by Becca = B = 74 hours

Put the value of B in eq 2

I.e  A = B - 15      

∴, A = 74 - 15

I.e A = 59

So,The time spend by Alexis = A  = 59 hours

Similarly

Put the value of B in eq 3

I.e  C = 4 + 2 B

∴   C = 4 + 2 × 74

i.e C = 152

So, The time spend by Cindy = C = 152 hours

Hence The time spend by Alexis is 59 hours  

The time spend by Becca is 74 hours    

The time spend by Cindy is 152 hours    Answer