Answer:[tex]W=1.93\times 10^9 J[/tex]
Explanation:
Given
Force [tex]F=1.6\times 10^{6} N[/tex]
one at an angle of [tex]13^{\circ}[/tex] East of North and another at [tex]13^{\circ}[/tex] West of North
Net Force is in North Direction
[tex]F_{net}=2F\cos 13[/tex]
Forces in horizontal direction will cancel out each other
thus Work done will be by north direction forces
[tex]W=2F\cdot \cos 30\cdot s[/tex]
here [tex]s=0.7 km[/tex]
[tex]W=2\times 1.6\times 10^{6}\cdot \cos 30\cdot 700[/tex]
[tex]W=1.93\times 10^9 J[/tex]
