Answer:
La cantidad de Ca3 (P04) 2 equivalente a 15, 4 moles es de 4774 gramos.
Explanation:
We need the weights of the elementos Ca, P and O, for calculate the weight of 1 mol:
Weight Ca=40 g
Weight P=31 g
Weight 0 = 16 g
Weight Ca3(PO4)2 = 3 x 40 g + 2 x (31 g + 4 x 16 g)
Weight Ca3(PO4)2 =310 g
1 molCa3(PO4)2---- 310 g
15, 4 mol Ca3(PO4)2-----x=(15, 4 molx 310 g)/1 mol = 4774 g
