Answer:
0.375
Step-by-step explanation:
Given that F is the event that a student is enrolled in a finance course, and let S be the event that a student is enrolled in a statistics course.
It is known that 40% of all students are enrolled in a finance course and 35% of all students are enrolled in statistics. Included in these numbers are 15% who are enrolled in both statistics and finance.
P(F) = 0.40: P(S) = 0.35: P(FS) = 0.15
A student is randomly selected, and it is found that the student is enrolled in finance.
Probability that this student is also enrolled in statistics/ student is enrolled in finance.
= [tex]\frac{P(FS)}{P(F)} \\=\frac{0.15}{0.40} \\=0.375[/tex]
(Using conditional probability formula)