6 L of oxygen (O₂)
Explanation:
We have the following chemical reaction:
2 Mg + O₂ → 2 MgO
Now we calculate the number of moles of magnesium:
number of moles = mass / molar weight
number of moles of Mg = 12 / 24 = 0.5 moles
Taking in account the chemical reaction we devise the following reasoning:
if 2 moles of Mg react with 1 mole of O₂
then 0.5 moles of Mg react with X moles of O₂
X = (0.5 × 1) / 2 = 0.25 mole of O₂
mass = number of moles × molar weight
mass of O₂ = 0.25 × 32 = 8 g
Knowing the information given by the problem that 32 g of O₂ takes up 24 liters of space, we devise the following reasoning:
if 32 g of O₂ takes up 24 liters of space
then 8 g of O₂ takes up Y liters of space
Y = (8 × 24) / 32 = 6 L of O₂
Learn more about:
balancing chemical reactions
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