Suppose a computer has 16-bit instructions. The instruction set consists of 32 different operations. All instructions have an opcode and two address fields (allowing for two addresses). The first of these addresses must be a register, and the second must be memory. Expanding opcodes are not used. The machine has 16 registers. What is the maximum allowable size for memory?
Since the computer has a 16-bit instruction set, and has 16 registers, it will require four (4) bits for a register address, the maximum allowable size for memory therefore will be 4X16 = 64
