Respuesta :
The question is incomplete, here is a complete question.
An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.
Answer : The new volume of the balloon is 25.7 L
Explanation :
Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
[tex]V\propto T[/tex]
or,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1[/tex] = initial volume of gas = 27.8 L
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]13^oC=273+13=286K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-9^oC=273+(-9)=264K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{27.8L}{286K}=\frac{V_2}{264K}[/tex]
[tex]V_2=25.7L[/tex]
Therefore, the new volume of the balloon is 25.7 L
