Answer:
4.23 x 10^7 m
Explanation:
Time period, T = 24 hours = 24 x 3600 seconds
the time period of the satellite is given by
[tex]T = 2\pi \sqrt{\frac{r^{3}}{GM}}[/tex]
where, r be the radius of orbit, M be the mass of earth and G be the universal gravitational constant.
[tex]24\times 3600 = 2\times 3.14 \sqrt{\frac{r^{3}}{6.67\times 10^{-11}\times 6\times 10^{24}}}[/tex]
[tex]1.89\times 10^8= \frac{r^{3}}{6.67\times 10^{-11}\times 6\times 10^{24}}}[/tex]
r = 4.23 x 10^7 m
thus, the radius of the orbit is 4.23 x 10^7 m.
