Answer:
The length of segment AC is two times the length of segment A'C'
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor
Let
z ----> the scale factor
A'C' ----> the length of segment A'C'
AC ----> the length of segment AC
so
[tex]z=\frac{A'C'}{AC}[/tex]
we have that
[tex]z=50\%=50/100=\frac{1}{2}[/tex] ---> the dilation is a reduction, because the scale factor is less than 1 and greater than zero
substitute
[tex]\frac{1}{2}=\frac{A'C'}{AC}[/tex]
[tex]AC=2A'C'[/tex]
therefore
The length of segment AC is two times the length of segment A'C'
Answer:
D) 1 /2 (AC) = A'C'
Step-by-step explanation:
The solution is 1 /2 AC = A'C'. The side lengths in ΔABC are twice the side lengths in ΔA'B'C'.
