Answer:
The first triangle.
Step-by-step explanation:
The sides LM, MN, and LN of Δ LMN have sides of lengths 15√2, 15 and 15 respectively.
Now, in the first graph, the sides of the graphed triangle are 3√2, 3 and 3 respectively.
So, the ratio of the corresponding sides is [tex]\frac{15\sqrt{2} }{3\sqrt{2} } = \frac{15}{3} = \frac{15}{3} = 5[/tex]
Therefore, the first graphed triangle is similar to Δ LMN using the SSS similarity theorem. (Answer)
