Answer:
A. x = 9
D. x = 0
Step-by-step explanation:
The formula to solve a quadratic equation of the form
[tex]ax^{2} +bx+c=0[/tex]
is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]
in this problem we have
[tex]6x^{2} -54x=0[/tex]
so
[tex]a=6\\b=-54\\c=0[/tex]
substitute in the formula
[tex]x=\frac{-(-54)(+/-)\sqrt{-54^{2}-4(6)(0)}} {2(6)}[/tex]
[tex]x=\frac{54(+/-)54} {12}[/tex]
[tex]x=\frac{54(+)54} {12}=9[/tex]
[tex]x=\frac{54(-)54} {12}=0[/tex]
therefore
The solutions are x=0 and x=9
