Answer:
The answer is False
Explanation:
For a infinite sheet of charges, the electric field is perpendicular to its surface. To calculate the electric field, we use a Gaussian surface (cylinder), getting that
[tex]\Phi=E2A=\frac{\sigma A}{\epsilon_{0}}[/tex]
from where
[tex]E=\frac{\sigma}{2\epsilon_{0}}[/tex]
Then the field calculated is one half of the field of a conductor charged with [tex]\sigma[/tex], this means that the magnitude of the charged conductor is
[tex]E=\frac{\sigma}{\epsilon_{0}}[/tex]
Therefore the answer is False.
