Answer:
Explanation:
The relationship between angle and wavelength for maxima and minima in Young's double slit experiment is given by
For constructive interference
[tex]d\sin \theta =m\lambda [/tex]
For Destructive interference
[tex]d\sin \theta =(m+\frac{1}{2})\lambda [/tex]
where [tex]\lambda =wavelength[/tex]
[tex]d=slit\ width[/tex]
m=order of maxima and minima
for second order maxima i.e. [tex]m=2[/tex]
For smallest separation taking [tex]\lambda =400 nm, \theta =90^{\circ} [/tex]
[tex]d\sin 90=2\times 400\times 10^{-9}[/tex]
[tex]d=0.8\times 10^{-6}[/tex]
[tex]d=0.8\mu m[/tex]
