Respuesta :
Answer:
Both reaches equilibrium simultaneously.
Explanation:
Given that,
First stretch spring= 20 cm
Second stretch spring = 10 cm
Two equal masses are suspended from identical spring.
Their forces constants are equal time period for oscillation
Using formula of time period
[tex]T=2\pi\sqrt{\dfrac{m}{k}}[/tex]
Where, T = time period
m = mass
k = spring constant
Time period independent of amplitude.
Hence, Both reaches equilibrium simultaneously.
Answer:
both reaches at the same time.
Explanation:
The time period of the mass is given by
[tex]T=2\pi \sqrt{\frac{m}{K}}[/tex]
where, K be the spring constant and m be the mass attached.
As both the masses are same and springs are identical so K is same for both the springs.
Thus, both the masses will reach at the equilibrium position at the same time.
