Choose two positive integers a and b, making sure that a<5 and b>80 . The width of a rectangular computer screen is a inches more than its height. If the area of the screen is is b square inches, determine the dimensions of the computer screen.

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Answer:

Dimensions of the screen are a minimum of 10 inches wide by 8 inches high. The difference between the height and width will be 2 inches

Step-by-step explanation:

[tex]Height = H[/tex]

[tex]Width = H + a[/tex]

[tex]Area = Height x Width[/tex]

[tex]b = H * (H + a)[/tex]

[tex]b = H^{2} + aH[/tex]

[tex]H^{2} + aH > 80[/tex]

[tex]H^{2} + aH - 80 > 0[/tex]

a<5 means 'a' can be a = 1, 2, 3, 4

Solving for H for each option of 'a' will give values of 'H' using the quadratic formula below

[tex]H = \frac{-b\±\sqrt{b^{2}-4ac}}{2a}[/tex]

As 'a' and 'b' must be positive integers, H and W must be positive integers as well,

[tex]a = 1, H = 8.46, H = -9.46 [/tex]

[tex]a = 2, H = 8, H = -10 [/tex]

[tex]a = 3, H = 7.57, H = -10.57 [/tex]

[tex]a = 4, H = 7.17, H = -11.17 [/tex]

Based on above possible answers:

[tex]a=2, H=8[/tex]

[tex]W = H + a[/tex]

[tex]W = 8 + 2[/tex]

[tex]W = 10[/tex]

Dimensions of the screen are a minimum of 10 inches wide by 8 inches high. The difference between the height and width will be 2 inches