The y-coordinate is 16
Given that a line with slope 3 passes through point (0, 10)
To find the y-coordinate of the point on the line with x-coordinate 2
Which means the point is (2, y)
Let us find the required y co-ordinate using slope formula
The slope of line is given as:
For a line containing points [tex](x_1 , y_1)[/tex] and [tex](x_2 , y_2)[/tex] is given as:
[tex]\text {slope}=m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
[tex]\text {Here } x_{1}=0 ; y_{1}=10 ; x_{2}=2 ; y_{2}=y[/tex]
Given that slope "m" = 3
Substituting the values we get,
[tex]\begin{array}{l}{3=\frac{y-10}{2-0}} \\\\ {3=\frac{y-10}{2}} \\\\ {6=y-10} \\\\ {y=10+6=16}\end{array}[/tex]
Thus the y-coordinate is 16
