For this case we have that by definition, the equation of the line in the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It is the slope of the line
b: It is the cut-off point with the y axis
According to the statement, the line goes through the following points:
[tex](x_ {1}, y_ {1}) :( 1,1)\\(x_ {2}, y_ {2}) :( 0, -3)[/tex]
We found the slope:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-3-1} {0-1} = \frac {-4} {- 1 } = 4[/tex]
Thus, the equation is of the form:
[tex]y = 4x + b[/tex]
We substitute one of the points and find b:
[tex]-3 = 4 (0) + b\\b = -3[/tex]
Thus, the equation is of the form:
[tex]y = 4x-3[/tex]
Answer:
[tex]y = 4x-3[/tex]
