Answer:
2.51 atm is the tire pressure at 273 K.
Explanation:
Using ideal gas equation:
PV = nRT
where,
P = Pressure of gas =?
V = Volume of gas = 10.0 L
n = number of moles of gas = 1.12 moles
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas = 273 K
Putting values in above equation, we get:
[tex]P=\frac{1.12 mole\times 0.0821 L atm/mol K\times 273 K}{10.0 L}[/tex]
P = 2.51 atm
2.51 atm is the tire pressure at 273 K.
