The population of a small town was 10,800 in 2002. Since then, the population has decreased at a
rate of 2.5% each year. Write an exponential function to model the situation. Select the correction
equation.
A. p=10800(0.975)'
B. p=10800(0.25)'
C. p=1080(0.975)'
D. p=10800(1.025)'​

Respuesta :

Answer:

The exponential function to model the situation is                                        p = 10800[tex](0.975)^{\textrm t}[/tex]

Step-by-step explanation:

Given as :

The population of small town in 2002 = 10,800

The rate of decrease in population = r = 2.5%

Let The number of years of population decrease = t years

Let The population after n years = p

Now, According to question

The population after n years = The population of small town in 2002 × [tex](1-\dfrac{\textrm rate}{100})^{\textrm time}[/tex]

or, p = 10800 × [tex](1-\dfrac{\textrm r}{100})^{\textrm t}[/tex]

or, p = 10800 × [tex](1-\dfrac{\textrm 2.5}{100})^{\textrm t}[/tex]

or,  p = 10800 × [tex](0.975)^{\textrm t}[/tex]

∴ p = 10800[tex](0.975)^{\textrm t}[/tex]

Hence, The exponential function to model the situation is p = 10800[tex](0.975)^{\textrm t}[/tex]  . Answer

achezz

Step-by-step explanation:

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