contestada

Calculate the molar mass of a gas
with 0.4 g mass and 280 mL of
volume at standard temperature
and pressure (STP).​

Respuesta :

Answer:

MOLAR MASS = 32 g/mol

Explanation:

Condition of standard temperature and pressure(STP) are as follow:

Temperature = 273 K

Pressure = 1 atm (or 100000 Pa)

Here atm is atmosphere and Pa is Pascal

STP conditions arte used for measuring gas density and volume using Ideal Gas Law.Here 1 mole of ideal gas occupies 22.4 L of volume.

According toi Ideal Gas Equation :

PV = nRT

where P = pressure, n= number of moles, V = volume ,R= Ideal Gas Constant and T= temperature

[tex]n=\frac{PV}{RT}[/tex]

From question:

V=280 ml = 0.28 L

P = 1 atm

R=0.08205 L atm/K mol

T=273 K

Putting values in above formula :

[tex]n=\frac{1\times .280}{0.08205\times 273}[/tex]

n = 0.0125 moles

Now [tex]n=\frac{given\ mass}{Molar\ mass}[/tex]

[tex]Molar\ mass=\frac{given\ mass}{n}[/tex]

given mass = 0.4 g (given)

[tex] Molar\ mass=\frac{0.4}{0.0125}[/tex]

On solving we get:

Molar mass = 32 g/mol