Answer:
Length of Major Axis: 6√2
Length of Minor Axis: 4√2
Step-by-step explanation:
The general equation of the ellipse is: [tex]$ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 $[/tex] where [tex]$ a > b $[/tex].
Then the major axis is along [tex]$ x - axis $[/tex].
If the equation of the ellipse of of the form [tex]$ \frac{x^2}{b^2} + \frac{y^2}{a^2} = 1 $[/tex] where [tex]$ a > b $[/tex].
In this case, the equation of the major axis is along the [tex]$ y - axis $[/tex].
Here, the given equation of the second form.
The length of the major axis = 2a
The length of the minor axis = 2b
The given equation of the ellipse is:
[tex]$ \frac{(x - 3)^2}{18} + \frac{(y + 4)^2}{32} = 1 $[/tex]
Therefore, [tex]$ a^2 = 32 $[/tex] and [tex]$ b^2 = 18 $[/tex].
The length of the major axis = 2(√32) = 6√2
The length of the minor axis = 2(√18) = 4√2
