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What mass of steam is required to release
4.16×105
kJ of heat energy on condensation?
Answer in units of g.

50 POINTS PLUS BRAINLIEST & THANKSSS

Respuesta :

Well if it is 4.16 you would need 40.7 kJ/mol since 497000J/40700 J/mol = 12.21 mil and 12.21 x 18.02 =220 g steam at 100 deg C
facundo3141592

The mass needed to release 4.16*10^5 kJ of energy due to condensation is 18,300 grams.

How to find the mass of water?

We know that the latent heat of condensation (energy released by condensation) of vapor of water is:

2,260 kJ/kg

This means, if 1 kilogram of vapor of water is condensed, 2,260 kJ are released.

Now, Let's find the mass of water M such that:

M*2,260 kJ/kg = 4.15*10^5 kJ

M = (4.15*10^15 kJ)/(2,260 kJ/kg) = 1.83*10^2 kg

But we want this quantity in grams, so we need to apply a change of units:

1 kg = 1000g

Then the mass in grams is:

M = 1.83*10^2*(1000g) = 1.83*10^5 g = 18,300 g

If you want to learn more about latent heat, you can read:

https://brainly.com/question/87248

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