Respuesta :
Answer:
A) The sum or difference of the numbers is [tex]\frac{1}{2}[/tex] , option B
B) The total distance cover by Tom is 1 [tex]\frac{2}{35}[/tex] miles
C) The longer duration of Tom on Monday than Tuesday is [tex]\frac{5}{8}[/tex] hours , option B
Step-by-step explanation:
Given as :
A) The given benchmarks as 0 , [tex]\frac{1}{2}[/tex] , 1
From the given number , the mid number is [tex]\frac{1}{2}[/tex]
So, The sum of the number = 0 + [tex]\frac{1}{2}[/tex]
I,e The sum of the number = [tex]\frac{1}{2}[/tex]
And The difference of number = 1 - [tex]\frac{1}{2}[/tex]
Or, The difference of number = [tex]\frac{2 - 1}{2}[/tex]
Or, The difference of number = [tex]\frac{1}{2}[/tex]
Hence The sum or difference of the numbers is [tex]\frac{1}{2}[/tex] Answer
B) The distance cover by Tom on Monday = [tex]\frac{1}{5}[/tex] miles
The distance cover by Tom on Tuesday = [tex]\frac{6}{7}[/tex] miles
So, The total distance cover = The distance cover on Monday + The distance cover on Tuesday
I.e The total distance cover = [tex]\frac{1}{5}[/tex] miles + [tex]\frac{6}{7}[/tex] miles
Now, taking LCM
Or, The total distance cover = [tex]\frac{7 + 30}{35}[/tex] miles
Or, The total distance cover = [tex]\frac{37}{35}[/tex] miles
I.e The total distance cover = 1 [tex]\frac{2}{35}[/tex] miles
Hence The total distance cover by Tom is 1 [tex]\frac{2}{35}[/tex] miles Answer
C) The time period of Tom reading on Monday = [tex]\frac{7}{8}[/tex] hours
The time period of Tom reading on Tuesday = [tex]\frac{2}{8}[/tex] hours
The longer duration of Tom on Monday than Tuesday = x hours
So, x = The time period of Tom reading on Monday - The time period of Tom reading on Tuesday
I.e x = [tex]\frac{7}{8}[/tex] hours - [tex]\frac{2}{8}[/tex] hours
∴ x = [tex]\frac{7 - 2}{8}[/tex] hours
I,e x = [tex]\frac{5}{8}[/tex] hours
So, The longer duration of Tom on Monday than Tuesday = x = [tex]\frac{5}{8}[/tex] hours
Hence The longer duration of Tom on Monday than Tuesday is [tex]\frac{5}{8}[/tex] hours . option B Answer
