Answer:
The number of coins each she have are 10 dimes coin and 14 nickel coins.
Step-by-step explanation:
Given:
Minh has a coin collection of dimes and nickels worth $1.70.
The number of nickels is four more than the number of dimes.
Now, to find each coins she have.
Let the number of dimes be [tex]x[/tex].
And the number of nickels be [tex]4+x[/tex].
As the value of dimes = $0.10, and the value of nickel = $0.05.
Now, according to question:
[tex]0.10x+0.05(4+x)=1.70[/tex]
⇒[tex]0.10x+0.20+0.05x=1.70[/tex]
⇒[tex]0.15x+0.20=1.70[/tex]
Subtracting both sides by 0.20 we get:
⇒[tex]0.15x=1.50[/tex]
Dividing both sides by 0.15 we get:
⇒[tex]x=10[/tex].
Number of dimes = 10.
Number of nickel = [tex]4+x=4+10=14.[/tex]
Therefore, the number of coins each she have are 10 dimes coin and 14 nickel coins.
