Answer:
16 people
Step-by-step explanation:
This is a set problem
let first session be a
let second session be b
128 people attended at least one session = a∪b
a. 3/4 attended both session 1&2 = a∩b
b. 7/8 attended session 2 = p(b) i.e population b
c x attended session 1 = p(a) i.e. population a
lets get the figures.
lets substitute into the equation
let p(a) be x
128 = x + 112 - 96
128 = x + 16
x = 112 - no of people that attended the morning session.
But to find those that ONLY attended morning session
x - a∩b
112 - 96 = 16
Answer:
16 people attended the morning session only
Step-by-step explanation:
Total number of people attending the seminar = 128
Let M represent those dat attended the morning session.
Let A represent those that attended the afternoon session.
We are told that 3/4 of the people attended both sessions.
3/4*128 = 96
96 people attended both sessions
We are also told that 7/8 people attended afternoon session.
7/8*128 = 112
112 people attended the afternoon session.
To find those that attended the morning session only, we will use a Venn diagram
x -96 + 96 + 16 = 128
x = 128 -16
x = 112
Those that attended the morning session only = x - 96
= 112 - 96
= 16
16 people attended the morning session only
