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A plane has an airspeed of 120 km divided by hkm/h. It is flying on a bearing of 81degrees° while there is a 27 km divided by h27 km/h wind out of the northeast​ (bearing 225degrees°​). What are the ground speed and the bearing of the​ plane?

Respuesta :

Answer:

Ground speed is 61.67 km /h.

Step-by-step explanation:

Ground speed of aircraft is obtained b the sum of aircraft speed minus the current speed and direction.

For this the given formula is

81-27 cos (255 - 81 )

53.704 km/h

27 sin ( 225 - 81 ) = 2.822 km /h

so ground speed = [tex]\sqrt{(53.704 ^2 + 2.822)^2}[/tex]

= 61.67 km /h

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